From what height, h, should a rail-cart fall to complete a loop-the-loop of radius r without falling off a the track? Assume the track on which the rail-cart travels is smooth and express h in terms of r.

This question combines the principles of energy conservation and circular motion. The insight is to realise the condition for which the rail-cart will fall off of the track - when there is no contact force between the cart and track at the apex of the loop.Energy of cart at top of track: mgh Energy of cart at apex of loop: mg(2r) + 0.5mv2Hence energy conservation implies that mgh = mg(2r)Newton's Second Law at apex of the loop: Fcentripetal = mv2/r = mg - FcontactSetting Fcontact = 0 and substituting v2 = g into energy conservation equation gives h = 2.5r

BR

Related Physics A Level answers

All answers ▸

How would we calculate the distance covered by a train that starts at rest, then accelerates to 5km/hr in 30 mins then stays at this constant speed for 12 minutes?


How do I solve a problem about a mass on a slide?


What's the difference between Potential Difference and Electromotive Force


Whats the effective resistance in a parallel and series circuit with a cell and two 12 ohms resistors ?