Derive the mgh approximation for gravitational potential energy.

Newton's law of gravitation -> GPE = GMm/r - GMm/(r+h)GPE = GMm(1/r - 1/(r+h))GPE = GMm(h)/(r(r+h))r >> h -> GPE ~ (m)(GM/r^2)h = mgh

IS
Answered by Inigo S. PAT tutor

1986 Views

See similar PAT University tutors

Related PAT University answers

All answers ▸

A matchbox of height h and uniform density stands on its end on a table with coefficient of friction μ. For accelerating it horizontally, at acceleration a, whilst upright, at which height y should the acceleration be applied?


Given that during a total solar eclipse the Sun is fully hidden by the Moon, calculate the radius of the Moon. (You may use the following: Solar radius 700,000 km, Sun-Earth distance 150,000,000 km, Moon-Earth distance 400,000 km)


If water is trapped between two planes on a train, and the train decelerates at 4ms^-2. What angle does the surface of the water make with the horizontal?


Question below as would not fit in here


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences