A 80kg man is hanging from two 1.5m ropes that lie at 60 degrees from the horizontal. What is the tension in each rope required to prevent the man from dropping?

The man is 80kg so the downward force exerted by his weight is 80g (where g is the force of gravity equalling 9.8 Newtons (2dp)). Therefore the upward force exerted by each rope must equal 40g. Using trigonometry Sin(60)= 40g/T where T= the tension in the rope.Rearrange to make T the subject: 40g/Sin(60)= 452.64

DD
Answered by Dominic D. Physics tutor

1640 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A child is standing on a walkway that is moving at 2 metres per second and decides to turn around and walk back to the start at 2 metres per second. Explain why the child cannot reach the start of the walkway at this speed.


A car of mass 800 kg is accelerated horizontally by constant net force of 1920 N for 9 s. It then breaks for 2 s, but drives off a 5 m high cliff. If μ = 0.85, what is the total horizontal distance travelled by car and its velocity? Ignore air resistance.


A man weighing 600N steps on a scale that contains a spring. The spring is compressed 1cm under their weight. Find the force constant of the spring and total work done on its compression.


Derive the kinetic theory equation pV=Nm/3(crms2) for an ideal gas.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences