How to solve a standard first order differential equation?

First we must ensure that the differential is i the standard form of y' + p(x) y = f(x)The we use the integration factor I(x) = e to the integral of p(x)we then realise that if we differentiate this we will get I'(x) = p(x)* e to the integral of p(x) which is equal to I(x)*p(x)we then multiply the equation through by I(x) giving i(x) y' + I(x)*p(x) y = f(x) I(x)the left hand side can be simplified by the product rule of differentiation and we can then integrate through to find our answer

JB

Related Further Mathematics A Level answers

All answers ▸

Finding modulus and argument of complex number (x+iy)


Given sinhx = 0.5(e^x - e^-x), express its inverse, arcsinhx in terms of x.


f(x) = 9x^3 – 33x^2 –55x – 25. Given that x = 5 is a solution of the equation f(x) = 0, use an algebraic method to solve f(x) = 0 completely.


A curve has polar equation r = 1 + cos THETA for 0 <= THETA <= 2Pi. Find the area of the region enclosed by the curve