Find the magnitude of the force on an electron that is travelling with velocity 2 x 10^4 ms^(-1) in the x direction through a uniform magnetic field of strength 2T in the y direction.

This question tells us we only need to consider the magnitude of the force, and since the magnetic field and electron's velocity are perpendicular, we can simply use the equation

F = Bqv.

We have B = 2 Tq = 1.6 x 10-19 (the charge of an electron) and v = 2 x 10ms-1.

Substituting these values into the equation gives 

F = 2 * (1.6  x 10-19 ) * (2 x 104) = 6.4 x 10-15 N   (Remember your units!)

SH
Answered by Sally H. Physics tutor

18090 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A ball is thrown up with an initial velocity of 8 m/s and initial height of 1.5m above the ground. Calculate the maximum height the ball reaches and the time it takes to get there.


A child is going down a snowy hill on a sledge. Draw a free-body force diagram for the child and sledge.


Explain in terms of the motion of the molecules of the gas why the volume of gas must increase if the pressure is to remain constant as the gas is heated.


Particle A (60kg) moves right at 50m/s. It collides with particle B (250kg) moving left at 10m/s. If after the collision particle A moves left at 20m/s, calculate the final velocity of particle B


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning