Assuming the Earth is a perfect sphere of radius R. By how much would your mass (m), as given by a scale, change if you measured it on the north pole and on the equator?

The key observation here is that the Earth is spinning (angular velocity w) and so are you. The scale will give one number or another depending on the force that you exert on it, and by Newton's 3rd Law that is equal and opposite to the force that it exerts on you (i.e the normal force). On the north pole you are sitting just on the axis of rotation, so the centripetal force is zero. However, on the equator the centripetal force is no longer zero, so the normal has to be slightly smaller than your weight to keep you rotating. Bringing in some maths: Centripetal force= Your weight - normal N=mg-mRw^2=mg(1-rw^2/g)= what the scale "thinks" you weight. Hence, the readings are different by a factor of (1-rw^2/g)

JP
Answered by Javier P. Physics tutor

2456 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

How can we derive the 'suvat' equations of motion v=u+at and s=(u+v)t/2


How would we calculate the distance covered by a train that starts at rest, then accelerates to 5km/hr in 30 mins then stays at this constant speed for 12 minutes?


Two pellets are fired simultaneously from the horizontal, one is fired vertically at 100m/s and the other is fired at 200m/s at an angle theta from the horizontal. Calculate the angle of the second pellet if they both land at the same time.


How is a particle moving in circular motion accelerating but not varying speed?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning