A diver of mass 60kg stands on the end of a diving board (2m in length). Calculate the upward force exerted on the retaining spring which is 30cm from the start of the diving board.
Here we have a typical moments question. The start of the diving board is the pivot (draw a picture)To answer this question we need to know that sum of the clockwise moments must equal the sum of the anticlockwise moments (principle of moments) and we will need to know the equation: moment = force x perpendicular distance from the pivot, and the equationclockwise moments: moment from the man = (60 x 9.81*) * 2 anticlockwise moments: moment from the spring = upward force from spring * 0.3therefore: (60 x 9.81) * 2 = F * 0.3F = 3900N*9.81 is the gravitational field strength
SA
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