Why does sum(1/n) diverge but sum(1/n^2) converge?

Sum(1/n) is shown to converge by bracketing the series correctly and then comparing it with a series we know diverges. Sum(1/n^2) can be shown to converge via the integral test (using y=1/x^2), where the integral will be bigger than the series.

Related MAT University answers

All answers ▸

How do you differentiate ln(f(x))? Tricks like these occur commonly in STEP questions (including one I was looking at earlier today).


How many 0's are at the end of 100! (100 factorial)?


How many distinct solutions does the following equation have? log(base x^2 +2) (4-5x^2 - 6x^3) = 2 a)None, b)1, c)2, d)4, e)Infinitely many


The inequality x^4 < 8x^2 + 9 is satisfied precisely when...