Make y the subject of the formula x = SQRT((y+1)/(y-2))

Square both sidesMultiply by the RHS denominator (x^2(y-2)) = y+1Expand your brackets y(x^2) - 2x^2 = y + 1Begin re-arranging towards making y the subject so moving y terms to the left would get you y(x^2 - 1) = 2x^2 +1isolate y, making it the subject, by dividing the co-efficient on both sides (div by (x^2 - 1)) y(x^2 - 1) = 2x^2 +1 (div by (x^2 - 1))y = (2x^2 +1)/(x^2 - 1)

YE
Answered by Youness E. Further Mathematics tutor

6901 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

(x+4)((x^2) - kx - 5) is expanded and simplified. The coefficient of the x^2 term twice the coefficient of the x term. Work out the value of k.


Find dy/dx when y=2x^(4)+3x^(-1)


A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.


Find the tangent to the equation y=x^2 -2x +4 when x=2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences