Make y the subject of the formula x = SQRT((y+1)/(y-2))

Square both sidesMultiply by the RHS denominator (x^2(y-2)) = y+1Expand your brackets y(x^2) - 2x^2 = y + 1Begin re-arranging towards making y the subject so moving y terms to the left would get you y(x^2 - 1) = 2x^2 +1isolate y, making it the subject, by dividing the co-efficient on both sides (div by (x^2 - 1)) y(x^2 - 1) = 2x^2 +1 (div by (x^2 - 1))y = (2x^2 +1)/(x^2 - 1)

YE
Answered by Youness E. Further Mathematics tutor

8171 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Find the gradient of the line x^2 + 3x - 6 at the point (5,34)


How do I find the limit as x-->infinity of (4x^2+5)/(x^2-6)?


Consider the Matrix M (below). Find the determiannt of the matrix M by using; (a) cofactor expansion along the first row, (b) cofactor expansion along the second column


The equation 3x^2 – 5x + 4 = 0 has roots P and Q, find a quadratic equation with the roots (P + 1/2Q) and (Q + 1/2P)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning