y = (x+4)(6x-7). By differentiating, find the x coordinate of the maximum of this equation.
y=(x+4)(6x-7)y=6x2+17x-28dy\dx = 12x + 17To find the x coordinate of the stationary points of y, let dy\dx=012x+17=0x=-17\12
AS
Answered by Anika S. • Further Mathematics tutor
2354 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸How would I solve the following equation d^2x/dt^2 + 5dx/dt + 6x = 0
Rationalise and simplify (root(3) - 7)/(root(3) + 1) . Give your answer in the form a + b*root(3) where a, b are integers.
Work out the equation of the tangent to the curve y=x^2+5x-8 at the point (2,6)
A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.