y = (x+4)(6x-7). By differentiating, find the x coordinate of the maximum of this equation.

y=(x+4)(6x-7)y=6x2+17x-28dy\dx = 12x + 17To find the x coordinate of the stationary points of y, let dy\dx=012x+17=0x=-17\12

AS
Answered by Anika S. Further Mathematics tutor

1534 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Work out the equation of the tangent to the curve y=x^2+5x-8 at the point (2,6)


Show that (n^2) + (n+1)^2 + (n+2)^2 = 3n^2 + 6n + 5, Hence show that the sum of 3 consecutive square numbers is always 2 away from a multiple of 3.


Given f(x)= 8 − x^2, solve f(3x) = -28


Find the tangent to the equation y=x^2 -2x +4 when x=2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences