Find the tangent to the equation y=x^2 -2x +4 when x=2

When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x

NN
Answered by Nabeel N. Further Mathematics tutor

1642 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


f'(x) = 3x^2 - 5cos(3x) + 90. Find f(x) and f''(x).


Rationalise and simplify (root(3) - 7)/(root(3) + 1) . Give your answer in the form a + b*root(3) where a, b are integers.


y = (x+4)(6x-7). By differentiating, find the x coordinate of the maximum of this equation.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences