Find the tangent to the equation y=x^2 -2x +4 when x=2
When X=2 Y=2^2-2(2)+4=4 So the coordinates are (2,4)Differentiate Y so dy/dx = 2x-2Tangent Gradient when x=2 is 2(2)-2=2 so m=2We need to find the y intercept to get out tangent equationso y=2x+c , we sub in our coordinates to get 4=2(2)+c , c=0So therefore the tangent equation is y=2x
NN
Answered by Nabeel N. • Further Mathematics tutor
2507 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Find any stationary points in the function f(x) = 3x^2 + 2x
How do I find the limit as x-->infinity of (4x^2+5)/(x^2-6)?
Solve these simultaneous equations: 3xy = 1, and y = 12x + 3
A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.