Diagram B (will be supplied) shows a light sensor potential divider. i) what is component A? ii) what is Vs?

i) Component A - Is an LDR - Light dependent resistorii) The voltage across both resistors is 9VWe know that because the resistors are in series that the sum of the voltage across the components is the total voltage drop. Ie Vr1 + Vr2 = 9. Ohms law tells us that V = IR, and as the resistors are in series we know the currents are the same. Therefore we can work out Vr1 and Vr2, as Ir1 and Ir2 are the same we can call them I. with the equations Vr1 + Vr2 = Vt and V = IR, we can find the equation for the voltage across Resistor 2 (LDR). From here on Vr1 = V1 and Vr2 = V2V1 + V2 = VtVt = IR1 + IR2Vt = I*(R1+R2)Eq 1: I = Vt/(R1+R2)Eq 2: Vt = IR1 + V2Vt = (vt/(R1+R2))R1 + V2Vt - (Vt/(R1+R2))R1 = V2V2 = (Vt(R1+R2) - VtR1)/(R1+R2)V2 = Vt(R2/(R1+R2))

LW
Answered by Linden W. Design & Technology tutor

1729 Views

See similar Design & Technology GCSE tutors

Related Design & Technology GCSE answers

All answers ▸

State two reasons why corrugated cardboard is used as packaging for cooked pizzas.


What is meant by an iterative design process?


State the method in which a product is blow moulded.


Using sketches to support your answer, explain the process of injection moulding


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning