Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML

Related Further Mathematics GCSE answers

All answers ▸

Work out the coordinates for the stationary point of y = x^2 + 3x + 4


Solve the simultaneous equations xy=2 and y=3x+5.


A curve is defined by the equation y = (x + 3)(x – 4). Find the coordinates of the turning point of the curve.


Finding the derivative of a polynomial.