Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML

Related Further Mathematics GCSE answers

All answers ▸

Find the General Second Order Differential Equation Using Substitution (A2 Further Maths)


y=(6x^9 +x^8)/(2x^4), work out the value of d^2y/dx^2 when x=0.5


A circle has equation x^{2}-8x+y^{2}-6y=d. A line is tangent to this circle and passes through points A and B, (0,17) and (17,0) respectively. Find the radius of the circle.


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.