Find the coordinates of the minimum point of the function y=(x-5)(2x-2)
At the minimum point the gradient is zero so dy/dx=0. To find dy/dx, first expand out the brackets so y=2x^2 - 12x + 10. Using differentiation dy/dx=4x - 12. At the minimum 4x-12=0 so 4x=12 therefore x=3. Put this back into the original equation to find the y value of the minimum point y=(3-5)(2x3-2)=-8
PC
Answered by Phoebe C. • Further Mathematics tutor
2594 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸How to solve the inequality 1 - 2(x - 3) > 4x
How do I know I can multiply two matrices and if so, how do I do it?
A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.
A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.