Find the coordinates of the minimum point of the function y=(x-5)(2x-2)
At the minimum point the gradient is zero so dy/dx=0. To find dy/dx, first expand out the brackets so y=2x^2 - 12x + 10. Using differentiation dy/dx=4x - 12. At the minimum 4x-12=0 so 4x=12 therefore x=3. Put this back into the original equation to find the y value of the minimum point y=(3-5)(2x3-2)=-8
PC
Answered by Phoebe C. • Further Mathematics tutor
2748 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Expand (2x+3)^4
Find any stationary points in the function f(x) = 3x^2 + 2x
Find dy/dx when y=2x^(4)+3x^(-1)
Consider the Matrix M (below). Find the determiannt of the matrix M by using; (a) cofactor expansion along the first row, (b) cofactor expansion along the second column