Given a list of N numbers, use a single list comprehension to produce a new list that only contains those values that are: (a) even numbers, and (b) from elements in the original list that had even indices .

A simple solution to this problem would be as follows [x for x in list[::2] if x%2 == 0] For example, given the following list: list = [ 1 , 3 , 5 , 8 , 10 , 13 , 18 , 36 , 78 ] The list comprehension [x for x in list[::2] if x%2 == 0] will evaluate to: [10, 18, 78] The expression works by first taking the numbers that are at the even indices, and then filtering out all the odd numbers.