Show that the matrix A is non-singular for all real values of a
Given: A = [a -5; 2 a+4]. 1) First find the determinant of A using the known formula => det A = a2+ 4a + 10. A singular matrix is one in which it's determinant equals zero (the determinant of a matrix is a number that captures information about the characteristics of the matrix). The roots of the quadratic are complex, so the graph never equals zero/ no real roots. Therefore it must be a non-singular matrix.
Related Further Mathematics A Level answers
All answers ▸How do I integrate (sin x)^6?
Solve for z in the equation sin(z) = 2
Given that p≥ -1 , prove by induction that, for all integers n≥1 , (1+p)^k ≥ 1+k*p.
A=[5k,3k-1;-3,k+1] where k is a real constant. Given that A is singular, find all the possible values of k.