Given the rate of thermal energy transfer is 2.7kW, the volume of the water tank is 4.5m^3, the water is at a temperature of 28oC, density of water is 1000kgm-3 & c=4200Jkg-1K-1. Calculate the rise in water temperature that the heater could produce in 1hr
The equations needed to solve this problem are outlined below. E = mc(T2 - T1) d = m/v P = E/tYou first need to work out the mass of the water. m = 1000 x 4.5 = 4500kg You then need to work out the amount of energy produced by the heater in one hour. 2700 = E / (60 x 60)E = 9.72 x 106JThe change in temperature of the water can then be calculated.9.72 x 106 = 4500 x 4200 x (T2 - T1)Change in T = 0.51K
JB
Related Physics A Level answers
All answers ▸Two people sit opposite each other on the edge of a rotating disk of radius, R, and negligible mass. One person has a mass of 40kg, the other of 50kg. The disk is rotating at 30 revs/min. What is the rotational kinetic energy if R=1.5m?
A light wave has a wavelength of 420nm, calculate the energy of this wave in joules.
What is the difference between a scalar and a vector?
A golf ball is hit at angle θ to the horizontal, with initial velocity u. Stating an assumption, show that the horizontal distance travelled by the ball is directly proportional to u^2.