Simplify and then solve by factorisation 3x(x+2)-7=2, to find x.
3x(x+2)-7=2 3x2+6x-7=2 3x2+6x-9=0 3(x2+2x-3)=0 [Divide by 3] (x2+2x-3)=0 (x+3)(x-1)=0 x= -3 x=1
IM
3x(x+2)-7=2 3x2+6x-7=2 3x2+6x-9=0 3(x2+2x-3)=0 [Divide by 3] (x2+2x-3)=0 (x+3)(x-1)=0 x= -3 x=1
