Solve these simultaneous equations; 2y + x = 8, 4 + 4y = 8x

equation 1: 2y + x = 8equation 2: 4 + 4y = 8xSolve by substitution;simplify equation 12y + x = 8 x = 8 - 2ysubstitute into equation 2 4 + 4y = 8(8 - 2y)4 + 4y = 64 - 16y 4 + 20y = 64 20y = 60 y = 3substitute y = 3 into x = 8 - 2y; x = 8 - 2(3) x = 8 - 6 x = 2

JH
Answered by Josephine H. Maths tutor

3949 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2-5x+6=0


If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?


Draw the graph for y = x^2 + 4x +2


A common question would be how to factorise into two brackets, for example x^2 + 5x = -6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences