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X^2+4x-21=0 Solve for x

Quadractics factorise into double brackets like (x-a)(x-b). We ave to find the facors of -21 which add to make +4. 7 and -3 suffice. (x-3)(x+7) Then x will be equal to 3 and -7 for the equation.

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simplify fully (x^2-5x+4)/(x^2-2x-8)

A right-angle triangle has three sides (diagram would be included). Side A = 3cm; Side B = 7cm. What is the length of Side C (the hypotenuse)? Give your answer to 2 d.p.

HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts

X^2+4x-21=0 Solve for x

Related Maths GCSE answers

simplify fully (x^2-5x+4)/(x^2-2x-8)

A right-angle triangle has three sides (diagram would be included). Side A = 3cm; Side B = 7cm. What is the length of Side C (the hypotenuse)? Give your answer to 2 d.p.

HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts

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