Solve the equation 18x^2-3x=6
First put the equation into the correct form by setting it to 0:18x^2-3x-6=0Look for the common factor in the equation and take it out:3(6x^2-x-2)Using the grid method (which I would show on whiteboard) factor the problem:3(3x-2)(2x+1)=0To find the values of x, set each bracket to equal zero and solve:3x-2=0, 3x=2, x=2/32x+1=0, 2x=-1, x=-1/2There are 2 possible values of x because this is a quadratic equation so looking at the graph of the equation we would be able to see that the graph crosses the x axis at 2 different points
GH
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