Solve x^2 = 4(x - 3)^2

Multiply out brackets
x2 = 4(x2 - 6x + 9)x2 = 4x2 - 24x + 36
Minus x2 from both sides 3x2 -24x + 36 = 0
Divide equation by 3x2 - 8x + 12 = 0
What 2 numbers add to make -8 and multiply to make 12? -6 and -2, so put these into the brackets(x - 2)(x - 6) = 0
One of the brackets must equal 0 sox - 2 = 0x = 2
x - 6 = 0x = 6
x = 2, 6

RH
Answered by Rosie H. Maths tutor

2623 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express the equation x^2+6x-12 in the form (x+p)^2+q


What is a limit


What is the correct answer if you rearrange the following, making "c" the subject? (3c+b)/2 = c + a


Solve the following simulateous equations: 3x+y=11 and 2x+y=8


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences