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Find the coordinates of the minimum point on the curve: y = x^2 - x - 2

Start with the given equation from the question and differentiate it with respect to x to give you:dy/dx = 2x - 1The value of this gives you the slope of the curve and we know that the minimum point has a sl...
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Answered by Alex R. Maths tutor
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A curve has an equation of y = 20x - x^2 - 2x^3, with one stationary point at P=-2. Find the other stationary point, find the d^2y/dx^2 to determine if point P is a maximum or minium.

We know that a stationary point is found when the gradient of the curve is equal to zero, this is found by equaling the derivative (dy/dx) equal to zero. Differentiating the expression will find a quadratic ...
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Answered by Georgia S. Maths tutor
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Consider the infinite series S=Σ(from n=0 to infinite) u(down n) where u(down n)=lim (from n π to (n+1) π) ((sin t)/t) dt. Explain why the series is alternating.

For the first part of the question we need to try and understand what is actually happening – we have the sum of an integral – where we are summing a sequence of definite integrals. So when n = 0 we have the...
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Answered by Stuart D. Maths tutor
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Find an equation of the curve with parametric equations x=3sin(A) and y=4cos(A), in the form bx^2+cy^2=d.

x 2 =9sin 2 (A) and y 2 =16cos 2 (A)Since sin 2 (A)+cos 2 (A)=116x 2 +9y 2 =16 x 916x 2 +9y 2 =144
PV
Answered by Pranav V. Maths tutor
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Integrate 1/x

ln|x| + c
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Answered by George G. Maths tutor
4200 Views