Find an equation of the curve with parametric equations x=3sin(A) and y=4cos(A), in the form bx^2+cy^2=d.
x2=9sin2(A) and y2=16cos2(A)Since sin2(A)+cos2(A)=116x2+9y2=16 x 916x2+9y2=144
PV
x2=9sin2(A) and y2=16cos2(A)Since sin2(A)+cos2(A)=116x2+9y2=16 x 916x2+9y2=144
