Find the coordinates of the minimum point on the curve: y = x^2 - x - 2

Start with the given equation from the question and differentiate it with respect to x to give you:dy/dx = 2x - 1The value of this gives you the slope of the curve and we know that the minimum point has a slope of zero. So by setting the differentiated equation to zero and rearranging the equation, the value of x can be found:2x - 1 = 02x = 1x = 0.5This value of x is the x coordinate of the minimum, to then get the corresponding y value, sub this value of x into the equation given in the question:y = x2 - x - 2y = 0.52 - 0.5 - 2 = -2.25So the coordinates of the minimum are (0.5,-2.25)

AR

Related Maths A Level answers

All answers ▸

How do I calculate where a function is increasing/decreasing?


Given y = 2x(x^2 – 1)^5, show that dy/dx = g(x)(x^2 – 1)^4 where g(x) is a function to be determined.


Find the first and second derivative of f(x) = 6/x^2 + 2x


If y = 4x^3 - 6x^2 + 7 work out dy/dx for this expression