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Three forces of magnitude 50N, PN, QN all act in a horizontal plane in equilibrium. The diagram shows the forces. DIAGRAM: QN = EAST, 50 = SOUTH, PN = 120 DEGREES ANTICLOCKWISE FROM QN a) Find P. b) Find Q.

a) Resolving vertically: Pcos(120-90)=50. Find P from this equation.b) Resolving horizontally: Psin(120-90)=Q. Find Q from this solution.
CJ
Answered by Chloe J. • Maths tutor
4415 Views

Why is (x^3 - 7x^2 +13x - 6) divisible with (x-2)?

If we look at the general form a polynom P(X) divides Q(x) if and only if Q(x) = P(x) * T(x).Assume P(x) = a n x n + a n-1 x n-1 + ... + a 1 x + a 0 . How do the roots of P(x) relate to the roots of Q(x), wh...
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Answered by Vlad-Mihai E. • Maths tutor
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A level Maths question - The graph of y=2sin(2x)+1 is rotated 360 degrees about the x-axis to form a solid. Find the volume enclosed by the curve, the co-ordinate axes and the line x=pi/2

First, recall that the formula for finding such a volume is pi times the integral from 0 to pi/2 of y^2 with respect to x. This leads to pi times the integral from 0 to pi/2 of 4sin^2(2x) + 4sin(2x) + 1 (thi...
RK
Answered by Robbie K. • Maths tutor
4156 Views

Prove the identity: (cos θ + sin θ)/(cosθ-sinθ) ≡ sec 2θ + tan 2θ

First rewrite right hand side in terms of sinθ and cosθ, because those are the terms we'll be dealing with on the left hand side: sec2θ+tan2θ = 1/cos2θ + sin2θ/cos2θ, so RHS = (1+sin2θ)/cos2θNow look at the ...
MM
Answered by Margot M. • Maths tutor
8652 Views

How would I go about solving 3(x-2) = x+7?

First of all, you want to try and get rid of the brackets so the equation is easier to simplify in the next steps. So you multiply the whole bracket by 3. So it is 3x-6 = x+7. Secondly, in order to solve the...
FA
Answered by Finn A. • Maths tutor
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