Three forces of magnitude 50N, PN, QN all act in a horizontal plane in equilibrium. The diagram shows the forces. DIAGRAM: QN = EAST, 50 = SOUTH, PN = 120 DEGREES ANTICLOCKWISE FROM QN a) Find P. b) Find Q.
a) Resolving vertically: Pcos(120-90)=50. Find P from this equation.b) Resolving horizontally: Psin(120-90)=Q. Find Q from this solution.
CJ
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