Top answers

A curve has equation y = 20x −x2 −2x3 . (A) Find the x-coordinates of the stationary points of the curve.

Firstly, differentiate the equation to find dy/dx. dy/dx = 20 - 2x - 6x 2 As dy/dx represents the gradient, we know that for a stationary point the gradient must be zero, hence for the stationary points, we ...
BW
Answered by Bradley W. • Maths tutor
6404 Views

f(x) is defined by f(x) = 3*x^3 + 2*x^2 - 7*x + 2. Find f(1).

f(1) = 3 1^3 + 2 1^2 - 7*1 + 2 = 3 + 2 - 7 + 2 = 0
DM
Answered by Dragos M. • Maths tutor
3575 Views

A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve

A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x 2 - 2x 3 A simple rule to find the differe...
HJ
Answered by Henry J. • Maths tutor
4581 Views

Find the equation of the line through the following points: (-2, -3) and (1, 5)

Note the formula: y - y 1 = m(x - x 1 )x, y, x 1, y 1 refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRearrange the formula to make 'm' the subject...
TO
Answered by Tise O. • Maths tutor
3789 Views

How should I go about solving a quadratic equation?

There are more ways how to solve such equation:You can use the quadratic formula after rearranging the equation into the standard form. That is the safest way because you just learn the formula and use it ov...
LM
Answered by Linda M. • Maths tutor
3457 Views