A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve
A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x2 - 2x3A simple rule to find the differential of the curve is to multiply that power by the value and drop that power by one. e.g. the differential of 2x3: dy/dx = 6x2.Therefore, dy/dx = 20 - 2x - 6x2.As the stationary point is when dy/dx = 0. Therefore, 20 - 2x - 6x2 = 0.factorise this quadratic. (x + 2 )(-6x + 10) = 0Therefore, the other stationary point is x = 10/6 which can be simplified to x = 5/3
HJ
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