Find the equation of the line through the following points: (-2, -3) and (1, 5)
Note the formula: y - y1 = m(x - x1)x, y, x1, y1 refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRearrange the formula to make 'm' the subject - m = y - y1 /(x - x1)Insert the value of 'm' you calculated as well as the (x1, y1) set of coordinates. Expand, simplify and rearrange the new equation to make 'y' the subject - you now have the equation of the line.
TO
Related Maths A Level answers
All answers ▸The equation of a curve C is (x+3)(y-4)=x^2+y^2. Find dy/dx in terms of x and y
Event A: a customer asks for help. Event B a customer makes a purchase. We know: p(B) = 0.2 and p(A) knowing that he has asked for help is 75%. What is the probability of a customer to ask for help and make a purchase?
Differentiate y=ln(x)+5x^2, and give the equation of the tangent at the point x=1
Find the value of dy/dx at the point where x = 2 on the curve with equation y = x^ 2 √(5x – 1).