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How do I work out (2+y)^4 using the binomial expansion?

We're going to use the binomial expansion formula, which is a lot easier to remember than it looks: (a+b) n =C 0 *a n *b 0 + C 1 *a (n-1) *b 1 + C 2 *a (n-2) *b 2 +....+ C n *a 0 b n Now let's apply this for...
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Answered by Andrew B. • Maths tutor
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Find dy/dx at t=3, where x=t^3-5t^2+5t and y=2t^2

Using the product rule, we find that dy/dx= dy/dt multiplied by dt/dx, where dt/dx is the reciprocal of dx/dt dx/dt= 3t^2-10t+5, dy/dt= 4t At t=3, dx/dt= 3(3)^2-10(3)+5=2, dy/dt= 4(3)= 12 Therefore, dt/dx= 1...
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Answered by Oore A. • Maths tutor
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Express 21/root7 in the form k root7.

21/root 7 = 21root7/7 = 3root7 k = 3
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Answered by Ally W. • Maths tutor
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Given that y = 5x(3) + 7x + 3, find A) dy/dx B) d2y/dx2

A) 15x 2 +7 B) 30x
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Answered by Ally W. • Maths tutor
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Given y = 2x^2 + 3x + 2 find dy/dx

To get dy/dx from a formula y in terms of x we must differentiate y with respect to x. Generic formula for term differentiation: d/dx(ax^b) = bax^b-1 = times the coefficient by the power and minus the power ...
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Answered by Alex O. • Maths tutor
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