Find dy/dx at t=3, where x=t^3-5t^2+5t and y=2t^2
Using the product rule, we find that dy/dx= dy/dt multiplied by dt/dx, where dt/dx is the reciprocal of dx/dt
dx/dt= 3t^2-10t+5, dy/dt= 4t
At t=3, dx/dt= 3(3)^2-10(3)+5=2, dy/dt= 4(3)= 12
Therefore, dt/dx= 1/2
dy/dx= dy/dt x dt/dx= 12 x 1/2= 6
OA
Related Maths A Level answers
All answers ▸It is given that n satisfies the equation 2*log(n) - log(5*n - 24) = log(4). Show that n^2 - 20*n + 96 = 0.
By writing tan x as sin x cos x , use the quotient rule to show that d dx ðtan xÞ ¼ sec2 x .
The General Form of the equation of a circle is x^2 + y^2 + 2gx +2fy + c = 0. Find the centre of the circle and the radius of the circle in terms of g f and c.
How do I draw and sketch an equation?