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The equation of a line is y=3x – x^3 a) Find the coordinates of the stationary points in this curve, stating whether they are maximum or minimum points b) Find the gradient of a tangent to that curve at the point (2,4)

a) A stationary point is any point on the curve that is flat, still, not increasing or decreasing. Another way to think of this is the gradient at a stationary point = 0 Firstly make an equation for your gra...
LC
Answered by Lauren C. • Maths tutor
8469 Views

Find the stationary pointsof the following: (y = x^3 - x^2 -16 x -17) and determine if each point is a maximum or minimum.

Notes; *Stationary (Turning) points are the points on the graph which are lowest or highest. (maximum or minima). *The gradient at a stationary point is zero. Steps: 1. Differentiate the function once to fin...
CM
Answered by Charlie M. • Maths tutor
4266 Views

find the value of dy/dx at the point (1,1) of the equation e^(2x)ln(y)=x+y-2

find dy/dx, algebraically manipulate the expression to get dy/dx in terms of x and y and then subsitute in the given point.
JG
Answered by James G. • Maths tutor
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Given that x=ln(t) and y=4t^3,a) find an expression for dy/dx, b)and the value of t when d2y/dx2 =0.48. Give your answer to 2 decimal place.

a) Firstly, differentiate x and y with respect to t. Giving you dx/dt = 1/t and dy/dt = 12t 2 dy/dx is found using the chain rule: dy/dx = dy/dt x dt/dx = 12t 3 b) You will need to differentiate dy/dx again ...
SW
Answered by Sara W. • Maths tutor
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Calculate the gradient of the function y=x^2+6x when y=-9

-9=x^2+6x 0=x^2+6x+9 0=(x+3)(x+3) when y=-9 x=3 dy/dx=2x+6 dy/dx=2(3)+6=12
HM
Answered by Hassan M. • Maths tutor
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