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Differentiate f(x) = 2xlnx.

Use the chain rule: f'(x) = v(du/dx) +u(dv/dx). Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x Using this information: f'(x) = 2lnx + 2x/x This simplifies to f'(x) = 2lnx +2.
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Answered by Tom V. Maths tutor
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∫(1 + 3√x + 5x)dx

For each term the aim is to raise the power of x by 1 and divide by the new power. For this question, each part of the expression can be looked at seperately to make things a bit easier: ∫(1 + 3√x + 5x)dx = ...
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Answered by Mary T. Maths tutor
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How do you find the equation of a line at a given point that is tangent to a circle?

This question may start by giving you an equation, which you need to write in the form of the standard equation of a circle (usually by completing the square). This allows you to see the centre of the circle...
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Answered by Tom W. Maths tutor
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What's the integral of x^2 +3/x, with respect to x?

A: x 3 /3 + 3ln(x) + A. Step-by-step solution: Integral (x 2 +3/x dx) = [as integrals preserve sums] integral (x 2 dx) + integral (3/x dx) = [raise exponent by one, multiply by the reciprocal, add a constant...
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Answered by Marco G. Maths tutor
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How can I remember trig identities?

Trigonometric identities are sometimes tricky, as they are very hard to distinguish one from another. The best way of doing it is obviously by practising, but one thing I always find helpful is to give an ex...
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Answered by Marius S. Maths tutor
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