Differentiate f(x) = 2xlnx.
Use the chain rule: f'(x) = v(du/dx) +u(dv/dx).
Let u = 2x, du/dx = 2, v = lnx, dv/dx = 1/x
Using this information: f'(x) = 2lnx + 2x/x
This simplifies to f'(x) = 2lnx +2.
TV
Related Maths A Level answers
All answers ▸Find the equation of the line tangential to the function f(x) = x^2+ 1/ (x+3) + 1/(x^4) at x =2
What is the first derivative of y=5z(1+2z2)? Is this a minimum, maximum or turning point?
curve C with parametric equations x = 4 tan(t), y=5*3^(1/2)*sin(2t). Point P lies on C with coordinates (4*3^(1/2), 15/2). Find the exact value of dy/dx at the point P.
A curve C has equation y=(2x-3)^5. Find the equation of the normal of this curve at point P with y coordinate -32.