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Find the gradient of the line Y = X^3 + X + 6 when X = 4

Step 1: Differentiate the equation Y = X^3 + X + 6 to find the gradient of the line at any point. To do this, multiply each term of X by the old power and -1 from that power. This makes dy/dx = 3X^2 + 1.Step...
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Answered by Henry O. • Maths tutor
3765 Views

If 1/(x(a-x)) is equivalent to B(1/x + 1/(a-x)), Express 'B' in terms of 'a'

1/(x(a-x)) = B(1/x + 1/(a-x)) Note: the '≡' sign (defined equivalence) can be used in place of '=' but this is not necessary to achieve full marks.Step: multiply both sides by x(a-x)1 = (x(a-x))B(1/x + 1/(a-...
CG
Answered by Charles G. • Maths tutor
4303 Views

Differentiate y = x sin(x)

The question is asking to differentiate which means find dy/dx. If we think about the differentiation rules we know about, we see that we should use the product rule as y is a product (multiplication) of two...
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Answered by Nathan T. • Maths tutor
7533 Views

If y=5x+4x^3, find dy/dx.

When asked to find dy/dx, this means to differentiate. Differentiation is also a method of calculating the gradient of a line. (dy/dx = gradient.) The rule of differentiation is as follows: Step 1 : Differen...
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Answered by Umair H. • Maths tutor
4632 Views

Solve the equation 2cos2(x) + 3sin(x) = 3, where 0<x<=π

x = π/6, 5π/6, π/2
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Answered by Ben C. • Maths tutor
6047 Views