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Find the gradient of the curve y=2sinx/x^3 at the point x=

To find the gradient of the curve we must differentiate the function. The function is in the form of a quotient, y=u/v, where u and v are functions of x. Therefore, we can use the quotient rule, dy/dx = (v (...
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Answered by Holly M. • Maths tutor
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Differentiate y=x^4sinx

Firstly, we must recognise that the function is in the form of a product, y=uv, where u and v are functions of x. Therefore, we can use the product rule, dy/dx = u (dv/dx) + v (du/dx). 2) We can write u = x^...
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Answered by Holly M. • Maths tutor
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Given that y= 5x^2 + 2x , find dy/dx

5x^2 becomes 2 5x as the 2 comes down and 2x becomes 2 as x becomes 1.dy/dx = 2 5x + 2=10x+2
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Answered by Camille D. • Maths tutor
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How do I find the inverse of a function?

To find the inverse of a function you need to rearrange from y= a function in terms of x to x= a function in terms of y and then when you write your answer it's important to set it in the form f^-1(x)= a fun...
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Answered by Natalie H. • Maths tutor
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Prove that 2 cot (2x) + tan(x) == cot (x)

(1) Aim to rearrange the right hand side (rhs) to make it look like the left hand side.LHS = 2 cot (2x) + tan (x)(2) Notice that the rhs is only in terms of x, whereas the right has a function involving 2x. ...
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Answered by Joseph C. • Maths tutor
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