Top answers

express (1+4(root7)) / (5+2(root7)) as a+b(root7), where a and b are integers

1+4(root7) x 5 - 2(root7) 5+2(root7) 5 - 2(root7) 5 - 2(root7) + 20(root7) - (8x7) 25 - (4x7) 5 +18(root7) - 56 -3 -51 + 18(root7) -317 - 6(root7)ie a = 17, b = -6
HB
Answered by Hannah B. • Maths tutor
4411 Views

A curve has equation y = 20x −x2 −2x3 . (A) Find the x-coordinates of the stationary points of the curve.

Firstly, differentiate the equation to find dy/dx. dy/dx = 20 - 2x - 6x 2 As dy/dx represents the gradient, we know that for a stationary point the gradient must be zero, hence for the stationary points, we ...
BW
Answered by Bradley W. • Maths tutor
6342 Views

f(x) is defined by f(x) = 3*x^3 + 2*x^2 - 7*x + 2. Find f(1).

f(1) = 3 1^3 + 2 1^2 - 7*1 + 2 = 3 + 2 - 7 + 2 = 0
DM
Answered by Dragos M. • Maths tutor
3506 Views

A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve

A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x 2 - 2x 3 A simple rule to find the differe...
HJ
Answered by Henry J. • Maths tutor
4504 Views

Find the equation of the line through the following points: (-2, -3) and (1, 5)

Note the formula: y - y 1 = m(x - x 1 )x, y, x 1, y 1 refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRearrange the formula to make 'm' the subject...
TO
Answered by Tise O. • Maths tutor
3711 Views