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A curve has equation x = (y+5)ln(2y-7); (i) Find dx/dy in terms of y; (ii) Find the gradient of the curve where it crosses the y-axis.

(i) To find the derivative we will use the product rule. Let u = y+5 and v=ln(2y-7). Then dx/dy = du/dy v + u dv/dy = ln(2y-7) + (y+5)*2/2y-7 (used the chain rule in 2nd term - can explain this on white boar...
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Answered by Szymon P. Maths tutor
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Solve the equation: log5 (4x+3)−log5 (x−1)=2.

As both terms on the left hand side have base 5 we know we can combine them. When dealing with logs, a minus means we can divide them, and a plus means we can multiply them. This will leave us with log5(4x+3...
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Answered by Hugh G. Maths tutor
9753 Views

Show that 1+cot^2(x)=cosec^2(x)

Need to remember that:sin 2 (x)+cos 2 (x)=1 (eq.1)Divide the whole eq.1 by sin 2 (x)to get:sin 2 (x)/sin 2 x+cos 2 (x)/sin 2 (x)=1 /sin 2 x Which is the same as:1+cot 2 x=cosec 2 x
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Answered by Tutor114151 D. Maths tutor
62303 Views

Find the stationary point(s) of the curve: y = 3x^4 - 8x^3 - 3.

Firstly. Recognise which method you should use to approach this question. In this case, you can find the stationary point of a curve where its gradient is 0 i.e. at a point where the gradient changes from po...
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Answered by Laurene L. Maths tutor
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OCR C2 2015 Question 8: (a) Use logarithms to solve the equation 2^(n-3) = 18,000 , giving your answer correct to 3 significant figures. (b) Solve the simultaneous equations log2(x) + log2(y) = 8 & log2(x^2/y) = 7.

(a) This question actually tells us what to do . It is very hard to miss " use logarithms to solve... ". So our first step is going to be to use logs (especially as we can also see that is very lit...
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Answered by Jonathan H. Maths tutor
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