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Differentiate y = x^3− 5x^2 + 3x

the rule for differentiating in terms of x is to multiply by the power then decrease the power by one. So going through the equation x^3 will be multiplied by 3 and go to x^2 so will be 3x^2. Then its import...
GD
Answered by Georgia D. Maths tutor
7707 Views

Supposing y = arcsin(x), find dy/dx

Suppose: y = arcsin(x) Then, x = sin(y) And, dx/dy = cos(y) ----- (1) Using: dy/dx = 1/(dx/dy); Thus 1 becomes: dy/dx = 1/cos(y) ------ (2) Using: sin^2(y) + cos^2(y) = 1; We can rearrange 2 to: dy/dx = 1/sq...
JN
Answered by James N. Maths tutor
7354 Views

Find the coordinates of the turning points of the curve y = 4/3 x^3 + 3x^2-4x+1

First differentiating by the rule that x n differentiates to nx n-1 we have that dy/dx = 4x 2 +6x-4. At the turning points of a curve the differential is equal to 0 so we set 0=dy/dx = 4x 2 +6x-4, by factori...
TE
Answered by Theo E. Maths tutor
9453 Views

integrate xcosx

use integration by parts
SB
Answered by Sebastian B. Maths tutor
3912 Views

Find the minimum and maximum points of the graph y = x^3 - 4x^2 + 4x +3 in the range 0<=x <= 5.

First, use the standard method of setting the derivative to be equal to 0 to find the stationary points. This yields the equation 3x^2 - 8x + 4 = 0 and so the stationary points are at x = 2/3 and 2 respectiv...
GM
Answered by Guy M. Maths tutor
6259 Views