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How do you solve simultaneous questions?

When an equation has two or more variables, for example and x and y, more than one equation is need to solve it. The number of equations needs is equal to the number of variables you have. For example, if yo...
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Answered by Elise S. • Maths tutor
4108 Views

How do I calculate where a function is increasing/decreasing?

This depends entirely on the gradient of the function, which is calculated as (dy/dx). At (dy/dx)= 0, the function is neither increasing nor decreasing, since the gradient is zero. The max number of stationa...
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Answered by Steve H. • Maths tutor
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Prove or disprove the following statement: ‘No cube of an integer has 2 as its units digit.’

This is a very standard proof question for the C3 exam. The first thing that I would do when I see wordy proof statements like this is to make sure I understand what it means. Maybe writing out the statement...
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Answered by Thomas D. • Maths tutor
7084 Views

Solve the simultaneous equations: (1) y – 2x – 4 = 0 , (2) 4x^2 + y^2 + 20x = 0

Rearrange (1): y=2x+4 Subsitute this into (2): 4x 2 +(2x+4) 2 +20x=0 Simplify and collect like terms: 8x 2 +36x+16=0 Factorise: (2x+1)(x+4)=0 Therefore: 2x+1=0 -> x=-0.5 and x+4=0 -> x=-4 Substitute th...
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Answered by Anastasia T. • Maths tutor
4440 Views

A small stone is projected verically upwards from a point O with a speed of 19.6ms^-1. Modeeling the stone as a particle moving freely under gravity find the time for which the stone is more than 14.6m above O

S = 14.7, U = 19.6, V =, A = -g, T = t using s = ut + 1/2 at^2 14.7 = 19.6t + 1/2 -g t^2 1/2 g t^2 - 19.6t + 14.7 = 0 t = (19.6 +- sqrroot(-19.6 2 - 4 * 0.5 * 9.8 * 14.7)) / 2 * 0.5 * 9.8 t = 1 and t = 3 The...
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Answered by Hamish B. • Maths tutor
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