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Solve for 0 =< x =< 360 16/(cos(x+25)+1) = 10, give answers to 2 d.p.

Rearrange to get cos(x+25) = 0.6 Use inverse cosine to get (x+25) = -53.13... 53.13... 306.86... 413.13... Isolate x to get x = -78.13... 28.13... 281.86... 388.13... Apply the limits and round the answers t...
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Answered by Barnaby W. • Maths tutor
4547 Views

if f(x) = 7x-1 and g(x) = 4/(x-2), solve fg(x) = x

fg(x) = 7(4/x-2) -1 = x 28/(x-2) - 1 = x 28/(x-2) = x +1 28 = (x+1)(x-2) 28 = x 2 - x - 2 0 = x 2 - x - 30 0 = (x-6)(x+5) x=6 x=-5
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Answered by Sophie W. • Maths tutor
16367 Views

Three forces (4i + 7j)N, (pi +5j)N and (-8i+qj) N act on a particle of mass 5 kg to produce an acceleration of (2i - j) m s 2 . No other forces act on the particle. Find the resultant force acting on the particle in terms of p and q. THEN find p and Q

Three forces : (4 i + 7 j )N , (p i +5 j) N , (-8 i +q j ) N Mass = 5 kg acceleration = (2 i - j ) A.Collect like terms (4+p-8) i +(7+5+q) j = (-4+p) i + (12+q) j B. Recal_ f=ma therefore: 5(2i-j)=(-4+p) i +...
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Answered by Shane L. • Maths tutor
9563 Views

When you integrate, why do you need to add a +C on the end?

Integration can be used to undo differentiation. So if you had an equation that was y=5x+2 and differentiated to get dy/dx=5. When you integrate it you would only get y=5x, so the +2 is lost, to make sure yo...
KM
Answered by Katie M. • Maths tutor
4279 Views

3(a+4)=ac+5f. Rearrange to make a the subject.

3(a+4)=ac+5f 3a+12=ac+5f 3a-ac=5f-12 a(3-c)=5f-12 a= (5f-12)/(3-c)
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Answered by Rumana R. • Maths tutor
4673 Views