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Differentiate the function f(x) = 2x^3 + (cos(x))^2 + e^x

When differentiating a function that is the sum of three different parts we can differentiate each part separately: a) 2x 3 is easy to differentiate. We remember the rule d/dx[ax b ] = abx b-1 . So 2x 3 --&g...
SP
Answered by Seth P. • Maths tutor
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How do you go about sketching a curve when all you are given is the equation?

- First start by examining the equation. Is it in a recognisable form e.g. the equation of a circle/elipse etc. - If not, is it in the form y = or x = (these are the most common forms)? These are the steps y...
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Answered by Trishla S. • Maths tutor
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Solve the equation 2ln2x = 1 + ln3. Give your answer correct to 2dp.

LHS: because alnx = lnx a , 2ln2x = ln(2x) 2 = ln4x 2 Now, because ln and e are inverse functions, we take both sides to the power of e. Therefore: e ln4x^2 = e 1 + ln3 4x 2 = e 1 + ln3 x 2 = (e 1 + ln3 ) / ...
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Answered by Shiv S. • Maths tutor
5160 Views

Integrate ⌠( xcos^2(x))dx

We must first use trigonometric identities to simplify cos 2 (x). We can use the formula cos(A+B) = cos(A)cos(B) - sin(A)sin(B) , where A=x and B=x , so that we get cos(2x) = cos 2 (x) - sin 2 (x) = 2cos 2 (...
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Answered by Daniel A. • Maths tutor
10986 Views

A curve C has equation y = (2 - x)(1 + x) + 3 . A line passes through the point (2, 3) and the point on C with x-coordinate 2 + h . Find the gradient of the line, giving your answer in its simplest form.

First we find the y coordinate which is a function of x: x = 2+ h so y = (2 - 2 - h)(1 + 2 + h) + 3 = -h 2 - 3h + 3 Now for the gradient, the line passes through points (2,3) and (2 + h, -h 2 - 3h + 3) dx = ...
RS
Answered by Ricardo S. • Maths tutor
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