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How do you find the turning points of a graph and how do you if the point is a maximum or a minimum?

Firstly you have to find the turning points of the graph. This is done by differentiating the equation of the line. Once you have found this first derivative, equate the equation to zero. Now solve the equat...
HH
Answered by Harry H. • Maths tutor
27039 Views

Integrate (x)(e^x) with respect to x and then integrate (x)(e^x) with respect to y.

i) By integration by parts, we see that it equals (x)(e^x)-(e^x)+C, where C denotes the constant of integration. ii) (x)(y)(e^x)+C, where C denotes the constant of integration.
RV
Answered by Rohan V. • Maths tutor
4893 Views

How do you find the possible values of cos(x) from 5cos^2(x) - cos(x) = sin^2(x)?

First, you start by replacing sin^2(x) with 1-cos^2(x) as you want the equation to be in terms of cos(x) and you know sin^2(x)+cos^2(x) = 1. Then you rearrange the equation to get 0 on one side so that you c...
GK
Answered by Gowri K. • Maths tutor
4791 Views

By completing the square, find the values of x that satisfy x^4 -8x^2 +15 = 0

x^4 -8x^2 +15 = 0, we rewrite the equation in square form as (x^2-4)^2 -16 +15 =0 (x^2 -4)^2 = 1 x^2 -4 = ±1 so x^2 = 4±1, (x^2 = 3 or x^2 = 5) Therefore x = {-√3, √3, -√5, √5)
CS
Answered by Callum S. • Maths tutor
3603 Views

Find the turning point of the function y=f(x)=x^2+4x+4 and state wether it is a minimum or maximum value.

In order to find turning points, we differentiate the function. Hence we get f'(x)=2x + 4. Setting f'(x)=0 we get x = -2 and inputting this into f(x) we get y = 0 therefore the turning point is (-2,0). To fi...
BA
Answered by Basim A. • Maths tutor
13749 Views