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Before you start it is best to gather as much information as you can about the function. The most important things to find are any roots - as these will tell where the graph should cross the axis - and the t...

Here we have an equation involving absolute values. As a general rule |a| = +a and |a| = -a. We can apply that to our RHS. In the first case we get that 3x + 4 = 3x - 11, however after we subtract 3x from bo...

Here z is a complex number, and therefore, z = a + b i. Thus, our equation becomes (a + b i)^2 = i. Expanding the brackets we get a^2 + 2 a b i + (b^2) (i^2) = i. Since i is the square root of -1, i^2 = the ...

when integrating you must add one to the power and divide by the new power. so y=(5x^(2 + 1))/3 + (x^(1+1))/2 + 2x + c now substitute 1 for x and 3 for y so 3= (5(1)^(2 + 1))/3 + ((1)^(1+1))/2 + 2(1) + c 3 =...

The key to answering this question is to recognise that a common substitution of u=sin(x) wont work straight away so we must write the integral in a different form. Knowing that cos(2x)=1-2sin^2(x), the sin^...