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find the value of x for when f(x)=0. f(x)=9x^(2)-4

since f(x)=0 write 9x 2 -4=0 move the x's to one side and the numbers to the other. so 9x 2 =4 then to get rid of the 9 divide both sides by 9 so x 2 =(4/9) then square root so x=sqrt(4/9) and simply by taki...
ZS
Answered by Zivanayi S. • Maths tutor
4322 Views

How would you differentiate f(x) = 2x(3x - 1)^2 using the chain rule?

In order to differentiate this expression, you need to use the chain rule. The chain rule gives: f'(x) = uv' + u'v. The u and the v are two parts of the original function f(x). The apostrophe ' at the end me...
SE
Answered by Sam E. • Maths tutor
16153 Views

Find the derivative of f where f(x)=a^x.

This is a difficult question that you only need to know the result of.However, it's a good exercise to derive it. Starting with f(x)=a x we can take the natural logarithm of both sides (so we can use one of ...
LR
Answered by Larry R. • Maths tutor
4811 Views

How would you express (11+x-x^2)/[(x+1)(x-2)^2] in terms of partial fractions?

The first thing to consider when converting an expression to impartial fractions is how many fractions you will have in the end. With linear (no powers) brackets, found in the denominator of your initial fra...
MM
Answered by Matthew M. • Maths tutor
7910 Views

f(x) = (4x + 1)/(x - 2). Find f'(x)

Quotient rule: (vu' - uv')/v^2 u = 4x + 1 u' = 4 v = x - 2 v' = 1 Input into formula: [(x - 2)(4) - (4x + 1)(1)](x - 2)^2 Simplify: [4x - 8 -4x - 1]/(x - 2)^2 = -9/(x - 2)^2
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Answered by Salah S. • Maths tutor
13670 Views