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Find the stationary points of y= 5x^2 + 2x + 7

Stationary points occur when the gradient is 0 so when dy/dx =0 therefore we need to find dy/dx.By using 'down and decrease', we bring down the power and multiply by the coefficient and then decrease the pow...
AM
Answered by Alexandra M. • Maths tutor
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If y=4x^3+3/x^2-3, what is dy/dx?

We know the rule for differentiation is, multiply by the power reduce the power by one. Although having several parts this looks confusing we just need to break it down. 4x^3 differentiates to 12x^2 followin...
Answered by • Maths tutor
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y = 2/x^3 find and expression for dy/dx

y = 2 x -3 simpler to differentiate in this form dy/dx = (-3)(2 x -4 ) multiply by power out the front and subtract one from the powerdy/dx = -6/x 4 simplified version of above equation
RB
Answered by Rufus B. • Maths tutor
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make into a cartesian equation= x=ln(t+3) y= 1/t+5

e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2
RP
Answered by Ryan P. • Maths tutor
5491 Views

Find the two real roots of the equation x^4 - 5 = 4x^2 . Give the roots in an exact form. [4]

x 4 - 5 = 4x 2 . In order to find the roots of this equation we must factorise it, and, to do so, it must be rearranged such that all the terms are on one side. Therefore, subtract 4x 2 from both sides to ob...
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Answered by Sanjay S. • Maths tutor
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