make into a cartesian equation= x=ln(t+3) y= 1/t+5

e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2

RP
Answered by Ryan P. Maths tutor

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integrate by parts the equation dy/dx = (3x-4)(2x^2+5).


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