make into a cartesian equation= x=ln(t+3) y= 1/t+5

e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2

RP
Answered by Ryan P. Maths tutor

4835 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is differentiation?


Find d^2y/dx^2 for y=4x^4−3x^3−6x^2+x


Evaluate the indefinite integral: ∫ (e^x)sin(x) dx


Find the equation to the tangent to the curve x=cos(2y+pi) at (0, pi/4)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences