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Find the stationary points of y= 5x^2 + 2x + 7

Stationary points occur when the gradient is 0 so when dy/dx =0 therefore we need to find dy/dx.By using 'down and decrease', we bring down the power and multiply by the coefficient and then decrease the pow...
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Answered by Alexandra M. Maths tutor
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If y=4x^3+3/x^2-3, what is dy/dx?

We know the rule for differentiation is, multiply by the power reduce the power by one. Although having several parts this looks confusing we just need to break it down. 4x^3 differentiates to 12x^2 followin...
Answered by Maths tutor
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y = 2/x^3 find and expression for dy/dx

y = 2 x -3 simpler to differentiate in this form dy/dx = (-3)(2 x -4 ) multiply by power out the front and subtract one from the powerdy/dx = -6/x 4 simplified version of above equation
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Answered by Rufus B. Maths tutor
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When do you use the passé composé or the imparfait and how do you form these two tenses?

The passé composé is used to describe a completed action in the past.To form the passé composé you will need the subject, the auxiliary and the past participle of the verb:e.g. J’ai joué (I played) – Je = th...
Answered by French tutor
2090 Views

A car is travelling at 20 m/s. The accelerator is applied, causing an acceleration of 2m/s^s. How fast is the car travelling after 10 seconds of acceleration?

Using the SUVAT equation: v = u + at v = ?u = 20a = 2t = 10 v = 40m/s
Answered by Physics tutor
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